问题
填空题
函数f(x)=
|
答案
f′(x)=
=-(ex+1)′(ex-1)-(ex+1)(ex-1)′ (ex-1)2 2ex (ex-1)2
故答案为-2ex (ex-1)2
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函数f(x)=
|
f′(x)=
=-(ex+1)′(ex-1)-(ex+1)(ex-1)′ (ex-1)2 2ex (ex-1)2
故答案为-2ex (ex-1)2