问题
选择题
已知函数f(x)=
|
答案
f(x)=
(x-1)(x-2) |
(x+1)(x+2) |
x2-3x+2 |
x2+3x+2 |
∴f′(x)=
(2x-3)(x2+3x+2)-(2x+3)(x2-3x+2) |
(x2+3x+2)2 |
6x2-12 |
(x2+3x+2)2 |
∴f′(1)=-
1 |
6 |
故选D
已知函数f(x)=
|
f(x)=
(x-1)(x-2) |
(x+1)(x+2) |
x2-3x+2 |
x2+3x+2 |
∴f′(x)=
(2x-3)(x2+3x+2)-(2x+3)(x2-3x+2) |
(x2+3x+2)2 |
6x2-12 |
(x2+3x+2)2 |
∴f′(1)=-
1 |
6 |
故选D