问题
选择题
已知函数f(x)=
|
答案
f(x)=
=(x-1)(x-2) (x+1)(x+2) x2-3x+2 x2+3x+2
∴f′(x)=
=(2x-3)(x2+3x+2)-(2x+3)(x2-3x+2) (x2+3x+2)2 6x2-12 (x2+3x+2)2
∴f′(1)=-1 6
故选D
已知函数f(x)=
|
f(x)=
=(x-1)(x-2) (x+1)(x+2) x2-3x+2 x2+3x+2
∴f′(x)=
=(2x-3)(x2+3x+2)-(2x+3)(x2-3x+2) (x2+3x+2)2 6x2-12 (x2+3x+2)2
∴f′(1)=-1 6
故选D