将饱和氯化钠溶液以惰性电极电解一段时间后停止电解，这时剩余的电解液体积为 200mL ，其溶液PH为13，
（1）在标准状况下能收集到的气体体积为 L，
（2）此时转移的电子为 mol。
（1）0.448 （2）0.02
考查根据方程式进行的有关计算。溶液PH为13，则溶液中OH－的浓度就是0.1mol/L，所以氢氧化钠的物质的量是0.02mol。因此根据电解饱和食盐水的方程式
2H2O+2Cl-
Cl2↑+H2↑+2OH-可知生成的氢气和氯气都是0.01mol，所以其体积是0.02mol/L×22.4L/mol＝0.448L。由方程式可知，生成1mol氢气，转移2mol电子，所以反应中转移电子是0.02mol。
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