问题 选择题 曲线y=xx-2在点(1,-1)处的切线方程为( )A.y=x-2B.y=-3x+2C.y=2x-3D.y=-2x+1 答案 y′=(xx-2)′=-2(x-2)2,∴k=y′|x=1=-2.l:y+1=-2(x-1),则y=-2x+1.故选:D