答案:C
设函数f(x)=x3-3ax+b(a≠0),
(Ⅰ)若曲线y=f(x)在点(2,f(2))处与直线y=8相切,求a,b的值;
(Ⅱ)求函数f(x)的单调区间与极值点.
— Is your photo in the drawer?
—________.
A.Yes, I am.
B.No,it is.
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