问题
选择题
已知x>0,y>0,lg2x+lg8y=lg2,则
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答案
∵lg2x+lg8y=lg2,∴lg(2x?8y)=lg2,∴2x+3y=2,∴x+3y=1.
∵x>0,y>0,∴
+1 x
=(x+3y)(1 3y
+1 x
)=2+1 3y
+3y x
≥2+2x 3y
=4,当且仅当x=3y=
?3y x x 3y
时取等号.1 2
故选C.
已知x>0,y>0,lg2x+lg8y=lg2,则
|
∵lg2x+lg8y=lg2,∴lg(2x?8y)=lg2,∴2x+3y=2,∴x+3y=1.
∵x>0,y>0,∴
+1 x
=(x+3y)(1 3y
+1 x
)=2+1 3y
+3y x
≥2+2x 3y
=4,当且仅当x=3y=
?3y x x 3y
时取等号.1 2
故选C.