A、B、C都是金属，把A浸入C的盐溶液中，A的表面有C析出，A与B和酸溶液组成原电池时，B为电池的负极。A、B、C金属的活动性顺序为 （ ）
A.A>B>C B.A>C>B C.B>A>C D.B>C>A
答案：C
题目分析：把A浸入C的硝酸盐溶液中，A的表面有C析出；说明金属A可以把金属C从其盐中置换出来，所以活泼性A＞C，A、B和稀硫酸组成原电池时，B为电池的负极，所以活泼性B＞A，A、B、C三种金属的活动性顺序为B＞A＞C。
故选C。
点评：本题考查判断金属活泼性的方法，可以根据所学知识进行回答，难度不大。
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| A: Nancy, where 1___ you go 2____ vacation last summer? B: I 3___ to New York City. A: Oh, 4___? Did you go to 5___ Park? B: Yes, I did. It’s beautiful. A: 6___ did you get there? B: I 7___ there by plane. It’s fast and safe. (又快又安全) A: Did you 8___ a good time there? B: Sure. And I’m 9___ for the next chance (机会) to go there. A: Oh, you're so 10___. | |||
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