问题
解答题
因式分
(1)ax2-4axy+4ay2
(2)ab+a+b+1.
答案
(1)原式=a(x2-4xy+4y2)
=a(x-2y)2;
(2)原式=a(b+1)+(b+1)
=(a+1)(b+1).
因式分
(1)ax2-4axy+4ay2
(2)ab+a+b+1.
(1)原式=a(x2-4xy+4y2)
=a(x-2y)2;
(2)原式=a(b+1)+(b+1)
=(a+1)(b+1).