问题
选择题
函数y=ln(x-1)+1,(x>1)的反函数为( )
A.y=ex-1+1(x>1)
B.y=ex-1+1(x∈R)
C.y=ex+1-1(x>1)
D.y=ex+1-1(x∈R)
答案
由函数f(x)=ln(x-1)+1,(x>1),
解得x-1=ey-1(y∈R),故x=ey-1+1,
所以所求反函数为f-1(x)=ex-1+1(x∈R),
故选B.
函数y=ln(x-1)+1,(x>1)的反函数为( )
A.y=ex-1+1(x>1)
B.y=ex-1+1(x∈R)
C.y=ex+1-1(x>1)
D.y=ex+1-1(x∈R)
由函数f(x)=ln(x-1)+1,(x>1),
解得x-1=ey-1(y∈R),故x=ey-1+1,
所以所求反函数为f-1(x)=ex-1+1(x∈R),
故选B.