问题
解答题
把下列各式分解因式:
(1)x3y-xy3
(2)(x2+4)-16x2
(3)x(y-z)-y(z-y)
答案
(1)x3y-xy3,
=xy(x2-y2),
=xy(x+y)(x-y);
(2)(x2+4)-16x2,
=(x2+4+4x)(x2+4-4x),
=(x+2)2(x-2)2;
(3)x(y-z)-y(z-y),
=x(y-z)+y(y-z),
=(x+y)(y-z).
把下列各式分解因式:
(1)x3y-xy3
(2)(x2+4)-16x2
(3)x(y-z)-y(z-y)
(1)x3y-xy3,
=xy(x2-y2),
=xy(x+y)(x-y);
(2)(x2+4)-16x2,
=(x2+4+4x)(x2+4-4x),
=(x+2)2(x-2)2;
(3)x(y-z)-y(z-y),
=x(y-z)+y(y-z),
=(x+y)(y-z).