问题
填空题
设x>0,y>0,且
|
答案
由
+1 x
=16,得:1 y
+1 16x
=1,1 16y
则x+y=(x+y)×1=(x+y)(
+1 16x
)=1 16y
+1 16
+(1 16
+y 16x
)≥x 16y
+21 8
=
?y 16x x 16y
+1 8
=1 8
.1 4
故答案为
.1 4
设x>0,y>0,且
|
由
+1 x
=16,得:1 y
+1 16x
=1,1 16y
则x+y=(x+y)×1=(x+y)(
+1 16x
)=1 16y
+1 16
+(1 16
+y 16x
)≥x 16y
+21 8
=
?y 16x x 16y
+1 8
=1 8
.1 4
故答案为
.1 4