问题
解答题
因式分
(1)3ax2+6axy+3ay2
(2)(a2+b2)2-4a2b2.
答案
(1)原式=3a(x2+2xy+y2)
=3a(x+y)2;
(2)原式=[(a2+b2)+2ab][(a2+b2)-2ab]
=(a+b)2(a-b)2.
因式分
(1)3ax2+6axy+3ay2
(2)(a2+b2)2-4a2b2.
(1)原式=3a(x2+2xy+y2)
=3a(x+y)2;
(2)原式=[(a2+b2)+2ab][(a2+b2)-2ab]
=(a+b)2(a-b)2.