问题 解答题
因式分
(1)
1
3
-3a2;                            
(2)9(x+y)2-4(x-y)2
(3)(x+y)2-4(x+y-1);                  
(4)-x2y+2xy2-y3
答案

(1)

1
3
-3a2

=

1
3
(1-9a2

=

1
3
(1+3a)(1-3a);                              

(2)9(x+y)2-4(x-y)2

=(3x+3y+2x-2y)(3x+3y-2x+2y)

=(5x+y)(x+5y);

(3)(x+y)2-4(x+y-1)

=(x+y)2-4(x+y)+4

=(x+y-2)2;                  

                

(4)-x2y+2xy2-y3

=-y(x2-2xy+y2

=-y(x-y)2

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