问题 选择题 函数f(x)=1ln(x-1)的反函数为( )A.y=e1x+1(x≠0)B.y=1ex+1(x≠0)C.y=e-1x+1(x≠0)D.y=e1x-1(x≠0) 答案 令y=f(x)=1ln(x-1),得x-1=e1y,x=1+e1y故反函数为y=1+e1x,由于原函数的值域不为0,故把函数的定义域应排除0∴y=e1x+1(x≠0)故选A.