问题
填空题
若x＜1，则y=
|
答案
∵x＜1，∴y=
=2x2-x+1 x-1
=2x+2x(x-1)+x-1+2 x-1
+1=-2(1-x+2 x-1
)+3≤-2•21 1-x
+3=-1．当且仅当x=0时取等号．(1-x)• 1 1-x
故答案为-1．
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若x＜1，则y=
|
∵x＜1，∴y=
=2x2-x+1 x-1
=2x+2x(x-1)+x-1+2 x-1
+1=-2(1-x+2 x-1
)+3≤-2•21 1-x
+3=-1．当且仅当x=0时取等号．(1-x)• 1 1-x
故答案为-1．