问题
填空题
分解因式:a4-4a3+4a2-9=______.
答案
a4-4a3+4a2-9,
=(a4-4a3+4a2)-9,
=a2(a-2)2-32,
=(a2-2a-3)(a2-2a+3),
=(a-3)(a+1)(a2-2a+3).
分解因式:a4-4a3+4a2-9=______.
a4-4a3+4a2-9,
=(a4-4a3+4a2)-9,
=a2(a-2)2-32,
=(a2-2a-3)(a2-2a+3),
=(a-3)(a+1)(a2-2a+3).