已知函数f(x)=log2x(x>1),若f-1(a)•f-1(b)=2,则
|
∵f(x)=log2x(x>1)
∴f-1(x)=2x(x>0)
∴f-1(a)f-1(b)=2a+b=2
∴a+b=1
∴
+1 a
=(a+b)(4 b
+1 a
)=5+4 b
+4a b b a
∵
>0,4a b
> 0b a
∴
+1 a
≥5+24 b
= 9(当且仅当
×4a b b a
=4a b
即a=b a
,b=1 3
时取等号)2 3
故选D
已知函数f(x)=log2x(x>1),若f-1(a)•f-1(b)=2,则
|
∵f(x)=log2x(x>1)
∴f-1(x)=2x(x>0)
∴f-1(a)f-1(b)=2a+b=2
∴a+b=1
∴
+1 a
=(a+b)(4 b
+1 a
)=5+4 b
+4a b b a
∵
>0,4a b
> 0b a
∴
+1 a
≥5+24 b
= 9(当且仅当
×4a b b a
=4a b
即a=b a
,b=1 3
时取等号)2 3
故选D