问题
解答题
分解因式: (1)y2-y+
(2)4x2-20x+25. (3)-4a2b+12ab2-9b3. (4)(a-b)2-2(a-b)+1. |
答案
(1)原式=(y-
)2;1 2
(2)原式=(2x-5)2;
(3)原式=-b(4a2-12ab+9b2)=-b(2a-3b)2;
(4)原式=(a-b-1)2.
分解因式: (1)y2-y+
(2)4x2-20x+25. (3)-4a2b+12ab2-9b3. (4)(a-b)2-2(a-b)+1. |
(1)原式=(y-
)2;1 2
(2)原式=(2x-5)2;
(3)原式=-b(4a2-12ab+9b2)=-b(2a-3b)2;
(4)原式=(a-b-1)2.