问题
解答题
(1)计算:
(2)分解因式:(x2-2x)2+2(x2-2x)+1 (3)先化简,再求值:
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答案
(1)原式=
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2 |
12 |
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2 |
|
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2 |
48 |
=2
6 |
1 |
2 |
3 |
2 |
6 |
=2
6 |
6 |
=-1-4
6 |
(2)原式=(x2-2x+1)2
=[(x-1)2]2
=(x-1)4;
(3)
x-1 |
x |
2x-1 |
x |
=
x-1 |
x |
x2-2x+1 |
x |
=
x-1 |
x |
x |
(x-1)2 |
=
1 |
x-1 |
当x=
5 |
1 | ||
|
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5 |