问题
填空题
已知x-y=1,xy=-2,则x3y-2x2y2+xy3的值是______.
答案
∵x3y-2x2y2+xy3,
=xy(x2-2xy+y2),
=xy(x-y)2,
∵x-y=1,xy=-2,
∴原式=-2×12=-2.
故答案为:-2.
已知x-y=1,xy=-2,则x3y-2x2y2+xy3的值是______.
∵x3y-2x2y2+xy3,
=xy(x2-2xy+y2),
=xy(x-y)2,
∵x-y=1,xy=-2,
∴原式=-2×12=-2.
故答案为:-2.