问题 解答题

因式分

(1)ax2-4axy-a+4ay2

(2)(a-b)(3a+b)2+(a+3b)2(b-a)

(3)(x2+3x-2)(x2+3x+4)-16.

答案

(1)ax2-4axy-a+4ay2

=a(x2-4xy-1+4y2),

=a[(x-2y)2-1],

=a(x-2y-1)(x-2y+1);

(2)(a-b)(3a+b)2+(a+3b)2(b-a),

=(a-b)(3a+b)2-(a+3b)2(a-b),

=(a-b)[(3a+b)2-(a+3b)2],

=(a-b)(3a+b+a+3b)(3a+b-a-3b),

=8(a-b)2(a+b);

(3)(x2+3x-2)(x2+3x+4)-16,

=[(x2+3x)2+2(x2+3x)-8]-16,

=(x2+3x)2+2(x2+3x)-24,

=(x2+3x+6)(x2+3x-4),

=(x2+3x+6)(x+4)(x-1).

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