问题
填空题
分解因式:
(1)x-x3=______
(2)xy-x-y+1=______.
答案
(1)x-x3=x(1-x2)=x(1+x)(1-x);
(2)xy-x-y+1=(xy-x)-(y-1)=x(y-1)-(y-1)=(x-1)(y-1).
故答案为:(1)x(1+x)(1-x);(2)(x-1)(y-1).
分解因式:
(1)x-x3=______
(2)xy-x-y+1=______.
(1)x-x3=x(1-x2)=x(1+x)(1-x);
(2)xy-x-y+1=(xy-x)-(y-1)=x(y-1)-(y-1)=(x-1)(y-1).
故答案为:(1)x(1+x)(1-x);(2)(x-1)(y-1).