问题
选择题
设a>0,b>0.若
|
答案
由题意知3a•3b=3,∴3a+b=3,∴a+b=1.
∵a>0,b>0,∴
+1 a
=(1 b
+1 a
)(a+b)=2+1 b
+b a
≥2+2a b
=4.当且仅当a=b=
×b a a b
时,等号成立. 1 2
故选D.
设a>0,b>0.若
|
由题意知3a•3b=3,∴3a+b=3,∴a+b=1.
∵a>0,b>0,∴
+1 a
=(1 b
+1 a
)(a+b)=2+1 b
+b a
≥2+2a b
=4.当且仅当a=b=
×b a a b
时,等号成立. 1 2
故选D.