问题
解答题
在实数范围内分解因式:x3-x2-3x+3.
答案
x3-x2-3x+3,
=(x3-x2)-(3x-3),
=x2(x-1)-3(x-1),
=(x-1)(x2-3),
=(x-1)(x+
)(x-3
).3
在实数范围内分解因式:x3-x2-3x+3.
x3-x2-3x+3,
=(x3-x2)-(3x-3),
=x2(x-1)-3(x-1),
=(x-1)(x2-3),
=(x-1)(x+
)(x-3
).3