问题
填空题
设P(x,y)为函数y=x2-1(x>
|
答案
由题意,m=
+3x+y-5 x-1
=6+x+3y-7 y-2
+y-2 x-1 x-1 y-2
∵x>
,∴y>23
∴6+
+y-2 x-1
≥6+2x-1 y-2
=8
×y-2 x-1 x-1 y-2
当且仅当
=y-2 x-1
,即y=x+1时,m取得最小值为8x-1 y-2
∵y=x2-1(x>
)3
∴x=2,y=3
∴P(2,3)
故答案为:(2,3)