问题 解答题
7
12
÷[
3
4
-(
11
12
-
1
2
)]

0.65×6.4-6.5×0.64+65×9%
[4
5
9
-(2
2
5
+0.64)÷3
1
25
+
5
6
]×4.5

1-2+3-4+5-6+…+2009-2010+2011
1
10×13
+
1
13×16
+
1
16×19
+…+
1
34×37

1
1
2
+2
1
6
+3
1
12
+…+9
1
90
+10
1
110
答案

(1)

7
12
÷[
3
4
-(
11
12
-
1
2
)],

=

7
12
÷[
3
4
-
5
12
],

=

7
12
÷
1
3

=

7
12
×3,

=

7
4

(2)0.65×6.4-6.5×0.64+65×9%,

=0.65×6.4-6.5×0.64+65×0.09,

=0.65×6.4-0.65×6.4+0.65×9,

=0.65×(6.4-6.4+9),

=0.65×9,

=0.65×(10-1),

=6.5-0.65,

=5.85;

(3)[4

5
9
-(2
2
5
+0.64)÷3
1
25
+
5
6
]×4.5,

=[4

5
9
-(2.4+0.64)÷3.04+
5
6
]×4.5,

=[4

5
9
-3.04÷3.04+
5
6
]×4.5,

=[4

5
9
-1+
5
6
9
2

=[

32
9
+
5
6
9
2

=

32
9
×
9
2
+
5
6
×
9
2

=16+3

3
4

=19

3
4

(4)1-2+3-4+5-6+…+2009-2010+2011,

=(2011-2010)+(2009-2008)+…+(7-6)+(5-4)+(3-2)+1,

=1+1+…+1,

=1×1005+1,

=1006;

(5)

1
10×13
+
1
13×16
+
1
16×19
+…+
1
34×37

=

1
3
×[(
1
10
-
1
13
)+(
1
13
-
1
16
)+(
1
16
-
1
19
)+…+(
1
34
-
1
37
)],

=

1
3
×[
1
10
-
1
37
],

=

1
3
×
27
370

=

9
370

(6)1

1
2
+2
1
6
+3
1
12
+…+9
1
90
+10
1
110

=(1+2+3+…+9+10)+(

1
2
+
1
6
+
1
12
+…+
1
90
+
1
110
),

=(1+10)×10÷2+(1-

1
2
+
1
2
-
1
3
+
1
3
-
1
4
+…+
1
9
-
1
10
+
1
10
-
1
11
),

=55+(1-

1
11
),

=55+

10
11

=55

10
11

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