问题
填空题
分解因式:x2-4y2+2x-4y=______.
答案
x2-4y2+2x-4y,
=(x2-4y2)+(2x-4y),
=(x+2y)(x-2y)+2(x-2y),
=(x-2y)(x+2y+2).
分解因式:x2-4y2+2x-4y=______.
x2-4y2+2x-4y,
=(x2-4y2)+(2x-4y),
=(x+2y)(x-2y)+2(x-2y),
=(x-2y)(x+2y+2).