问题
填空题
计算(1-
|
答案
(1-
)(1-1 22
)(1-1 32
)…(1-1 42
)(1-1 20042
)(1-1 20052
)1 20062
=
•22-1 22
•32-1 32
…42-1 42
•20052-1 20052 20062-1 20062
=
×1 2 2007 2006
=
.2007 4012
故答案为:
.2007 4012
计算(1-
|
(1-
)(1-1 22
)(1-1 32
)…(1-1 42
)(1-1 20042
)(1-1 20052
)1 20062
=
•22-1 22
•32-1 32
…42-1 42
•20052-1 20052 20062-1 20062
=
×1 2 2007 2006
=
.2007 4012
故答案为:
.2007 4012