问题
填空题
计算
|
答案
x4+4=(x2+2)2-(2x)2=(x2+2x+2)(x2-2x+2)=[(x+1)2+1][(x-1)2+1],
∴原式=
=(22+1)(42+1)(62+1)(82+1)…(382+1)(402+1) (42+1)(62+1)(82+1)(102+1)…(402+1)(422+1)
=22+1 422+1
.1 353
故答案为:
.1 353
计算
|
x4+4=(x2+2)2-(2x)2=(x2+2x+2)(x2-2x+2)=[(x+1)2+1][(x-1)2+1],
∴原式=
=(22+1)(42+1)(62+1)(82+1)…(382+1)(402+1) (42+1)(62+1)(82+1)(102+1)…(402+1)(422+1)
=22+1 422+1
.1 353
故答案为:
.1 353