不等式
|
∵
≥1⇔2x x-1
-1≥0⇔2x x-1
≥0,x+1 x-1
∴
或x+1≤0 x-1<0
,x+1≥0 x-1>0
∴x≤-1或x>1.
∴不等式
≥1的解集是{x|x≤-1或x>1}.2x x-1
故答案为:{x|x≤-1或x>1}.
不等式
|
∵
≥1⇔2x x-1
-1≥0⇔2x x-1
≥0,x+1 x-1
∴
或x+1≤0 x-1<0
,x+1≥0 x-1>0
∴x≤-1或x>1.
∴不等式
≥1的解集是{x|x≤-1或x>1}.2x x-1
故答案为:{x|x≤-1或x>1}.