问题
解答题
分解因式:
(1)x2-4(x-1)
(2)2x4-32y4.
答案
(1)x2-4(x-1)=x2-4x+4=(x-2)2;
(2)2x4-32y4=2(x4-16y4)=2(x2+4y2)(x2-4y2)=2(x2+4y2)(x+2y)(x-2y).
分解因式:
(1)x2-4(x-1)
(2)2x4-32y4.
(1)x2-4(x-1)=x2-4x+4=(x-2)2;
(2)2x4-32y4=2(x4-16y4)=2(x2+4y2)(x2-4y2)=2(x2+4y2)(x+2y)(x-2y).