问题 解答题

把下列各式分解因式:

①a2+10a+25

②m2-12mn+36n2

③xy3-2x2y2+x3y

④(x2+4y22-16x2y2

答案

①a2+10a+25,

=(a+5)2

②m2-12mn+36n2

=(m-6n)2

③xy3-2x2y2+x3y,

=xy(y2-2xy+x2),

=xy(x-y)2

④(x2+4y22-16x2y2

=(x2+4y2+4xy)(x2+4y2-4xy),

=(x+2y)2(x-2y)2

判断题
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