问题
解答题
把下列各式分解因式(任选一题做)
①(x2+y2)2-4x2y2
②3ax2+6axy+3ay2.
答案
①(x2+y2)2-4x2y2=(x2+y2+2xy)(x2+y2-2xy)=(x+y)2(x-y)2;
②3ax2+6axy+3ay2=3a(x2+2xy+y2)=3a(x+y)2.
把下列各式分解因式(任选一题做)
①(x2+y2)2-4x2y2
②3ax2+6axy+3ay2.
①(x2+y2)2-4x2y2=(x2+y2+2xy)(x2+y2-2xy)=(x+y)2(x-y)2;
②3ax2+6axy+3ay2=3a(x2+2xy+y2)=3a(x+y)2.