问题 解答题
分解因式及化简
(1)x3y-2x2y2+xy3
(2)a2(a-b)+4b2(b-a)
(3)
3
x+2
-
1
x-2
+
2x
x2-4
      
(4)
1
x+1
+
x2-x
x2-2x-3
÷
x
x-3
答案

(1)原式=xy(x2-2xy+y2)=xy(x-y)2

(2)原式=(a-b)(a2-4b2)=(a-b)(a+2b)(a-2b);

(3)原式=

3(x-2)-(x+2)+2x
(x+2)(x-2)
=
4(x-2)
(x+2)(x-2)
=
4
x+2

(4)原式=

1
x+1
+
x(x-1)
(x-3)(x+1)
x-3
x
=
1+x-1
x+1
=
x
x+1

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