问题
解答题
计算: (1)2sin30°+cot60°-
(2)|tan45°-tan60°|+
|
答案
(1)原式=1+
-1+13 3
=1+3 3
=
;3+ 3 3
(2)原式=
-1+3 (sin60°-1)2
=
-1+|3
-1|3 2
=
-1+1-3 3 2
=
.3 2
计算: (1)2sin30°+cot60°-
(2)|tan45°-tan60°|+
|
(1)原式=1+
-1+13 3
=1+3 3
=
;3+ 3 3
(2)原式=
-1+3 (sin60°-1)2
=
-1+|3
-1|3 2
=
-1+1-3 3 2
=
.3 2