问题
解答题
计算:(1)cos245°+sin60°•tan30°-tan30° (2)
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答案
(1)原式=
+1 2
- 1 2
=1-3 3
,3 3
(2)原式=
=-7-4
+13 2
-13 2
.3
计算:(1)cos245°+sin60°•tan30°-tan30° (2)
|
(1)原式=
+1 2
- 1 2
=1-3 3
,3 3
(2)原式=
=-7-4
+13 2
-13 2
.3