问题
解答题
因式分
(1)2x2+2x
(2)a3-a
(3)(x-y)2-4(x-y)+4
(4)x2+2xy+y2-9.
答案
(1)2x2+2x=2x(x+1)
(2)a3-a=a(a2-1)=a(a+1)(a-1)
(3)(x-y)2-4(x-y)+4=(x-y-2)2
(4)x2+2xy+y2-9=(x2+2xy+y2)-32=(x+y)2-32=(x+y+3)(x+y-3)
因式分
(1)2x2+2x
(2)a3-a
(3)(x-y)2-4(x-y)+4
(4)x2+2xy+y2-9.
(1)2x2+2x=2x(x+1)
(2)a3-a=a(a2-1)=a(a+1)(a-1)
(3)(x-y)2-4(x-y)+4=(x-y-2)2
(4)x2+2xy+y2-9=(x2+2xy+y2)-32=(x+y)2-32=(x+y+3)(x+y-3)