问题
解答题
计算:(1) 2sin30°+2cos60°+4tan45°;(2)sin30°+cos245°-
|
答案
(1)原式=2×
+2×1 2
+4×1=6.1 2
(2)原式=
+( 1 2
) 2-2 2
× ( 1 3
) 2=0.3
计算:(1) 2sin30°+2cos60°+4tan45°;(2)sin30°+cos245°-
|
(1)原式=2×
+2×1 2
+4×1=6.1 2
(2)原式=
+( 1 2
) 2-2 2
× ( 1 3
) 2=0.3