问题
解答题
计算题: (1)tan60°+2sin45°-2cos30°; (2)
|
答案
(1)原式=
+2×3
-2×2 2 3 2
=
+3
-2 3
=
.2
(2)原式=
+2×
-13 1+
•13 3 2
=
+(
-1)23 2 3
=2-
+3 3
=2.
计算题: (1)tan60°+2sin45°-2cos30°; (2)
|
(1)原式=
+2×3
-2×2 2 3 2
=
+3
-2 3
=
.2
(2)原式=
+2×
-13 1+
•13 3 2
=
+(
-1)23 2 3
=2-
+3 3
=2.