问题
解答题
因式分
(1)x2y-2xy2+y3;
(2)(x+2y)2-y2.
答案
(1)x2y-2xy2+y3,
=y(x2-2xy+y2),
=y(x-y)2;
(2)(x+2y)2-y2,
=(x+2y+y)(x+2y-y),
=(x+3y)(x+y).
因式分
(1)x2y-2xy2+y3;
(2)(x+2y)2-y2.
(1)x2y-2xy2+y3,
=y(x2-2xy+y2),
=y(x-y)2;
(2)(x+2y)2-y2,
=(x+2y+y)(x+2y-y),
=(x+3y)(x+y).