问题 解答题

因式分

(1)x2y-2xy2+y3

(2)(x+2y)2-y2

答案

(1)x2y-2xy2+y3

=y(x2-2xy+y2),

=y(x-y)2

(2)(x+2y)2-y2

=(x+2y+y)(x+2y-y),

=(x+3y)(x+y).

单项选择题
单项选择题