问题 填空题

因式分

(1)ax2-a=______;

(2)m2-4m+4=______;

(3)x2-5x+6=______;

(4)ac+bc+3a+3b=______.

答案

(1)ax2-a,

=a(x2-1),

=a(x+1)(x-1);

(2)m2-4m+4=(m-2)2

(3)x2-5x+6=(x-2)(x-3);

(4)ac+bc+3a+3b,

=(ac+bc)+(3a+3b),

=c(a+b)+3(a+b),

=(a+b)(c+3).

故答案为:(1)a(x+1)(x-1);(2)(m-2)2;(3)(x-2)(x-3);(4)(a+b)(c+3).

选择题
多项选择题