问题
解答题
求未知数Χ. ①32-0.4X=22 ②
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答案
(1)32-0.4X=22,
32-0.4x+0.4x=22+0.4x,
32-22=22+0.4x-22,
10=0.4x,
10÷0.4=0.4x÷0.4,
x=25;
(2)
:X=2:3 5
,1 3
2x=
×3 5
,1 3
2x=0.2,
2x÷2=0.2x÷0.2,
x=0.1.
求未知数Χ. ①32-0.4X=22 ②
|
(1)32-0.4X=22,
32-0.4x+0.4x=22+0.4x,
32-22=22+0.4x-22,
10=0.4x,
10÷0.4=0.4x÷0.4,
x=25;
(2)
:X=2:3 5
,1 3
2x=
×3 5
,1 3
2x=0.2,
2x÷2=0.2x÷0.2,
x=0.1.