问题
解答题
因式分
(1)x4-y4;
(2)(x2+4)2-16x2;
(3)3a3-6a2+3a.
答案
(1)x4-y4,
=(x2+y2)(x2-y2),
=(x2+y2)(x+y)(x-y);
(2)(x2+4)2-16x2,
=(x2+4x+4)(x2-4x+4),
=(x+2)2(x-2)2;
(3)3a3-6a2+3a,
=3a(a2-2a+1),
=3a(a-1)2.
因式分
(1)x4-y4;
(2)(x2+4)2-16x2;
(3)3a3-6a2+3a.
(1)x4-y4,
=(x2+y2)(x2-y2),
=(x2+y2)(x+y)(x-y);
(2)(x2+4)2-16x2,
=(x2+4x+4)(x2-4x+4),
=(x+2)2(x-2)2;
(3)3a3-6a2+3a,
=3a(a2-2a+1),
=3a(a-1)2.