问题 解答题
计算下列各式的值.
(1)3
1
2
log
3
4

(2)32+log35
(3)71-log75
(4)4
1
2
(log29-log25)
答案

(1)原式=3

1
2
log
3
4=3log
3
2
=32log32=3log322=3log34=4.

(2)原式=32+log35=323log35=9×5=45

(3)原式=71-log⁡75=7log⁡7

7
5
=
7
5

(4)4

1
2
(log⁡29-log⁡25)=2
1
2
(log⁡2
9
5
)
=2log⁡2
9
5
=
9
5

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