问题 解答题
计算下列各式的值
(1)[125
2
3
+(
1
2
)-2+(343)
1
3
]
1
2

(2)
2lg2+lg3
1+
1
2
lg0.36+
1
3
lg8
答案

(1)原式=[(53)

2
3
+4+(73)
1
3
]0.5=(25+4+7)0.5=6

(2)原式=

lg4+lg3
1+
1
2
lg0.62+
1
3
lg23
=
lg12
1+lg0.6+lg2
=
lg12
1+lg1.2
=
lg12
lg10+lg1.2
=
lg12
lg12
=1

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