问题 解答题
化简:
(1)mtan0°+xcos90°-psin180°-qcos270°-rsin360°
(2)tan20°+tan40°+
3
tan20°tan40°
(3)log2cos
π
9
+log2cos
9
+log2cos
9
答案

(1)mtan0°+xcos90°-psin180°-qcos270°-rsin360°=0

(2)tan20°+tan40°+

3
tan20°tan40°

=tan60°(1-tan20°tan40°)+

3
tan20°tan40°

=

3
-
3
tan20°tan40°+
3
tan20°tan40°

=

3

(3)cos

π
9
•cos
9
•cos
9
=
sin
π
9
•cos
π
9
•cos
9
•cos
9
sin
π
9
=
1
2
sin
9
•cos
9
•cos
9
sin
π
9
=
1
4
sin
9
cos
9
sin
π
9
=
1
8
sin
9
sin
π
9
=
1
8

log2cos

π
9
+log2cos
9
+log2cos
9
=log2(cos
π
9
•cos
9
•cos
9
)=log2
1
8
=-3

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