问题
解答题
化简: (1)mtan0°+xcos90°-psin180°-qcos270°-rsin360° (2)tan20°+tan40°+
(3)log2cos
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答案
(1)mtan0°+xcos90°-psin180°-qcos270°-rsin360°=0
(2)tan20°+tan40°+
tan20°tan40°3
=tan60°(1-tan20°tan40°)+
tan20°tan40°3
=
-3
tan20°tan40°+3
tan20°tan40°3
=3
(3)cos
•cosπ 9
•cos2π 9
=4π 9
=sin
•cosπ 9
•cosπ 9
•cos2π 9 4π 9 sin π 9
=
sin1 2
•cos2π 9
•cos2π 9 4π 9 sin π 9
=
sin1 4
cos4π 9 4π 9 sin π 9
=
sin1 8 8π 9 sin π 9 1 8
log2cos
+log2cosπ 9
+log2cos2π 9
=log2(cos4π 9
•cosπ 9
•cos2π 9
)=log24π 9
=-31 8