问题
选择题
若函数f(x)=logm(m-x)在区间[3,5]上的最大值比最小值大1,则实数m=( )
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答案
因为函数f(x)=logm(m-x)在区间[3,5]上是单调函数,m>5,所以logm(m-3)-logm(m-5)=1.
所以
=m,即m2-6m+3=0,又m>5,解得m=3+m-3 m-5
.6
故选B.
若函数f(x)=logm(m-x)在区间[3,5]上的最大值比最小值大1,则实数m=( )
|
因为函数f(x)=logm(m-x)在区间[3,5]上是单调函数,m>5,所以logm(m-3)-logm(m-5)=1.
所以
=m,即m2-6m+3=0,又m>5,解得m=3+m-3 m-5
.6
故选B.
选择正确的单词,把序号填在横线上。 | |
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