问题
解答题
计算题: (1)2log3
(2)(lg5)2+lg2×lg50. |
答案
(1)2log3
+log312-(0.7)0+0.25-1=-2log32+1+2log32-1+4=4.1 2
(2)(lg5)2+lg2×lg50=(lg5)2+lg2(lg5+1)=lg5(lg5+lg2)+lg2=lg5+lg2=1.
计算题: (1)2log3
(2)(lg5)2+lg2×lg50. |
(1)2log3
+log312-(0.7)0+0.25-1=-2log32+1+2log32-1+4=4.1 2
(2)(lg5)2+lg2×lg50=(lg5)2+lg2(lg5+1)=lg5(lg5+lg2)+lg2=lg5+lg2=1.