问题 填空题

计算:y3n-2÷2yn-3=______;(______)÷3x2y=2x.

答案

(1)y3n-2÷2yn-3=(1÷2)y3n-2-n+3=

1
2
y2n+1

(2)∵2x•3x2y=6x2+1y=6x3y.

故答案为:

1
2
y2n+1,6x3y.

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