问题
填空题
计算:y3n-2÷2yn-3=______;(______)÷3x2y=2x.
答案
(1)y3n-2÷2yn-3=(1÷2)y3n-2-n+3=
y2n+1;1 2
(2)∵2x•3x2y=6x2+1y=6x3y.
故答案为:
y2n+1,6x3y.1 2
计算:y3n-2÷2yn-3=______;(______)÷3x2y=2x.
(1)y3n-2÷2yn-3=(1÷2)y3n-2-n+3=
y2n+1;1 2
(2)∵2x•3x2y=6x2+1y=6x3y.
故答案为:
y2n+1,6x3y.1 2