问题
解答题
(a7+5a5+2a3)÷a3-(a6-7a4+3a2)÷2a2.
答案
原式=a7-3+5a5-3+2a3-3-
a6-2+1 2
a4-2+7 2
a2-23 2
=a4+5a2+2-
a4+1 2
a2+7 2
a2-23 2
=
a4+1 2
a2+17 2
.7 2
(a7+5a5+2a3)÷a3-(a6-7a4+3a2)÷2a2.
原式=a7-3+5a5-3+2a3-3-
a6-2+1 2
a4-2+7 2
a2-23 2
=a4+5a2+2-
a4+1 2
a2+7 2
a2-23 2
=
a4+1 2
a2+17 2
.7 2